Physica

00 Foundations

HVL, TVL and barrier n-value

HVL = ln 2 / μ, TVL = ln 10 / μ ≈ 3.32 HVL. n = log(1/B) / log 2 HVLs.

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Simulation

HVL, TVL and barrier n-value — Change the numbers; the scene follows.

Where it works

Treatment vault

Treatment vault

Primary barrier

In the bunker maze and barriers — time, distance, TVL, WUT, and weekly controlled-area dose.

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Formula

HVL=ln2μ,TVL=ln10μ3.32HVL,n=ln(1/B)ln2\mathrm{HVL}=\frac{\ln 2}{\mu},\quad \mathrm{TVL}=\frac{\ln 10}{\mu}\approx 3.32\,\mathrm{HVL},\quad n=\frac{\ln(1/B)}{\ln 2}

Variables

Results

  • HVL

    Half-value layer

    1.3863cm

  • TVL

    Tenth-value layer

    4.6052cm

  • n_HVL

    Number of HVLs

    6.6439

  • n_TVL

    Number of TVLs

    2

  • x

    Thickness required

    9.2103cm

Explanation

HVL=ln2μ,TVL=ln10μ3.32HVL,n=ln(1/B)ln2\mathrm{HVL}=\frac{\ln 2}{\mu},\quad \mathrm{TVL}=\frac{\ln 10}{\mu}\approx 3.32\,\mathrm{HVL},\quad n=\frac{\ln(1/B)}{\ln 2}

What it means

One half-value layer cuts intensity in half; one tenth-value layer cuts it by ten. Narrow-beam μ gives the theoretical HVL; broad-beam (with scatter) needs a larger effective HVL — the first HVL is smaller than the second because the beam hardens. Shielding reports quote TVLs of lead, concrete and steel at the design energy. This is a working relation in Radiation physics.

Where it is used

Clinically it sits on the Treatment vault — Primary barrier. In the bunker maze and barriers — time, distance, TVL, WUT, and weekly controlled-area dose. Radiation physics lives at the x-ray target, the linac head, and inside the patient: how a photon is born, how it scatters, and how it dies. Use these relations before you trust a spectrum, a wall, or a kV-versus-MV contrast argument.

Treatment vault · Open this machine

How to use it

Enter linear attenuation μ (cm⁻¹) and the desired transmission B. Read HVL, TVL and how many of each you need. 2 mm Pb at μ = 2.5 cm⁻¹ (≈100 keV) is several HVLs. Change one input and watch the curve and the simulation follow.

Symbols

  • μLinear attenuation0.5 cm⁻¹
  • BDesired transmission0.01

Worked example

A typical case from the default values: μ = 0.5 cm⁻¹ (Linear attenuation); B = 0.01 (Desired transmission). Substituting into the relation gives HVL = 1.3863 cm; TVL = 4.6052 cm; n_HVL = 6.6439; n_TVL = 2; x = 9.2103 cm. These are teaching numbers — align them with your machine.

Typical values give

  • HVL = 1.3863cm
  • TVL = 4.6052cm
  • n_HVL = 6.6439
  • n_TVL = 2
  • x = 9.2103cm

Where it comes from

The displayed formula is the working relation. HVL = ln 2 / μ, TVL = ln 10 / μ ≈ 3.32 HVL. n = log(1/B) / log 2 HVLs. Usual reference: NCRP 147 / 151. Derive it in the specialty lesson, then return here to pin the numbers.

Reference: NCRP 147 / 151

Assumptions & limits

Monoenergetic narrow beam. Real barriers use broad-beam TVLs that include Compton scatter buildup. First and equilibrium TVL differ (NCRP 151 tables). μ must match the material and the spectrum.

Pitfalls

Do not mix free-electron Compton kinematics with photoelectric-dominated kV imaging. Check keV versus MeV, and never treat a spectrum as one photon. Monoenergetic narrow beam. Real barriers use broad-beam TVLs that include Compton scatter buildup. First and equilibrium TVL differ (NCRP 151 tables). μ must match the material and the spectrum.

Keep this

Photons do not deposit dose; the electrons they set in motion do. Monoenergetic narrow beam. Real barriers use broad-beam TVLs that include Compton scatter buildup. First and equilibrium TVL differ (NCRP 151 tables). μ must match the material and the spectrum.

In this specialty

Radiation physics