Physica

00 Foundations

Parent–daughter decay (secular / transient)

Bateman solution for daughter activity starting from a pure parent.

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Simulation

Parent–daughter decay (secular / transient) — Change the numbers; the scene follows.

Where it works

Hot lab

Hot lab

Generator

At the Mo-99/Tc-99m generator — elution yield, secular equilibrium, Mo breakthrough.

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Formula

A2(t)=A1(0)λ2λ2λ1(eλ1teλ2t)A_2(t)=A_1(0)\frac{\lambda_2}{\lambda_2-\lambda_1}\left(e^{-\lambda_1 t}-e^{-\lambda_2 t}\right)

Typical values

Variables

Results

  • A₁

    Parent activity

    77.7203MBq

  • A₂

    Daughter activity

    78.5799MBq

  • A₂/A₁

    Ratio

    1.0111

Curve

Explanation

A2(t)=A1(0)λ2λ2λ1(eλ1teλ2t)A_2(t)=A_1(0)\frac{\lambda_2}{\lambda_2-\lambda_1}\left(e^{-\lambda_1 t}-e^{-\lambda_2 t}\right)

What it means

A parent nuclide decays to a radioactive daughter. If λ₂ ≫ λ₁ (half-life of the daughter much shorter) the system reaches secular equilibrium: A₂ ≈ A₁ after a few daughter half-lives, and they then decay together with the parent’s T½ — the ⁹⁹Mo/⁹⁹ᵐTc generator and ²²⁶Ra/²²²Rn. If the half-lives are comparable (λ₂ > λ₁ but not ≫) the equilibrium is transient: A₂ / A₁ = λ₂ / (λ₂ − λ₁) > 1 (¹³²Te/¹³²I). This is a working relation in Radiation physics.

Where it is used

Clinically it sits on the Hot lab — Generator. At the Mo-99/Tc-99m generator — elution yield, secular equilibrium, Mo breakthrough. Radiation physics lives at the x-ray target, the linac head, and inside the patient: how a photon is born, how it scatters, and how it dies. Use these relations before you trust a spectrum, a wall, or a kV-versus-MV contrast argument.

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How to use it

Enter A₁(0), the two half-lives and elapsed time, in the same time unit. Read A₁, A₂ and the ratio. Presets: Mo-99/Tc-99m (secular-ish, T½ 66 h / 6 h) and Te-132/I-132 (transient). Change one input and watch the curve and the simulation follow.

Symbols

  • A₁(0)Parent activity100 MBq
  • T½₁Parent half-life66 h
  • T½₂Daughter half-life6.02 h
  • tElapsed time24 h

Worked example

A typical case from the default values: A₁(0) = 100 MBq (Parent activity); T½₁ = 66 h (Parent half-life); T½₂ = 6.02 h (Daughter half-life); t = 24 h (Elapsed time). Substituting into the relation gives A₁ = 77.7203 MBq; A₂ = 78.5799 MBq; A₂/A₁ = 1.0111. These are teaching numbers — align them with your machine.

Typical values give

  • A₁ = 77.7203MBq
  • A₂ = 78.5799MBq
  • A₂/A₁ = 1.0111

Where it comes from

The displayed formula is the working relation. Bateman solution for daughter activity starting from a pure parent. Usual reference: Bateman 1910 / Cherry, Sorenson & Phelps. Derive it in the specialty lesson, then return here to pin the numbers.

Reference: Bateman 1910 / Cherry, Sorenson & Phelps

Assumptions & limits

Single daughter, branching ratio 1, no grand-daughter, A₂(0)=0. Mo-99 → Tc-99m actually has BR ≈ 0.86 to the metastable state. Generator elution resets A₂.

Pitfalls

Do not mix free-electron Compton kinematics with photoelectric-dominated kV imaging. Check keV versus MeV, and never treat a spectrum as one photon. Single daughter, branching ratio 1, no grand-daughter, A₂(0)=0. Mo-99 → Tc-99m actually has BR ≈ 0.86 to the metastable state. Generator elution resets A₂.

Keep this

Photons do not deposit dose; the electrons they set in motion do. Single daughter, branching ratio 1, no grand-daughter, A₂(0)=0. Mo-99 → Tc-99m actually has BR ≈ 0.86 to the metastable state. Generator elution resets A₂.

In this specialty

Radiation physics