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HVL, TVL and barrier n-value

HVL = 1.386 cm

HVL=ln⁡2μ,TVL=ln⁡10μ≈3.32 HVL,n=ln⁡(1/B)ln⁡2\mathrm{HVL}=\frac{\ln 2}{\mu},\quad \mathrm{TVL}=\frac{\ln 10}{\mu}\approx 3.32\,\mathrm{HVL},\quad n=\frac{\ln(1/B)}{\ln 2}

HVL = ln 2 / μ, TVL = ln 10 / μ ≈ 3.32 HVL. n = log(1/B) / log 2 HVLs.

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