Physica

05 Biology

Logistic TCP

TCP = 1 / (1 + exp(−4 γ₅₀ (D − TCD₅₀)/TCD₅₀)). Population dose–response.

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Simulation

Logistic TCP — Change the numbers; the scene follows.

Where it works

Linear accelerator

Linear accelerator

Isocenter

In the treated volume — tumour and OARs at isocenter, after the dose has been delivered.

Open this machine

Formula

TCP=[1+exp(4γ50DTCD50TCD50)]1\mathrm{TCP}=\left[1+\exp\left(-4\gamma_{50}\frac{D-TCD_{50}}{TCD_{50}}\right)\right]^{-1}

Variables

Results

  • TCP

    Tumour control probability

    0.7374

  • TCP

    TCP

    73.74%

Curve

Explanation

TCP=[1+exp(4γ50DTCD50TCD50)]1\mathrm{TCP}=\left[1+\exp\left(-4\gamma_{50}\frac{D-TCD_{50}}{TCD_{50}}\right)\right]^{-1}

What it means

A logistic (or probit) of dose is how empirical tumour-control series are fit when you do not want to commit to a clonogen number. TCD₅₀ is the dose that controls 50% of tumours; γ₅₀ is the normalised slope at that point (typical 1.5–3). It is the tumour-side twin of the logistic NTCP already in the library. Poisson TCP (the other calculator) is more mechanistic but needs N₀ and α. This is a working relation in Radiobiology.

Where it is used

Clinically it sits on the Linear accelerator — Isocenter. In the treated volume — tumour and OARs at isocenter, after the dose has been delivered. Radiobiology sits between the prescription and the organ-at-risk: LQ, BED, EQD2, and why 2 Gy is not 2 Gy if the fraction size changed. Use it to compare regimens, not to invent one.

Linear accelerator · Open this machine

How to use it

Enter D, TCD₅₀ and γ₅₀. A node-positive H&N series might have TCD₅₀ = 62 Gy, γ₅₀ = 2. Read TCP and the steepness in % per % dose. Change one input and watch the curve and the simulation follow.

Symbols

  • DDose70 Gy
  • TCD_5050% control dose62 Gy
  • γ_50Normalised slope2

Worked example

A typical case from the default values: D = 70 Gy (Dose); TCD_50 = 62 Gy (50% control dose); γ_50 = 2 (Normalised slope). Substituting into the relation gives TCP = 0.7374; TCP = 73.74 %. These are teaching numbers — align them with your machine.

Typical values give

  • TCP = 0.7374
  • TCP = 73.74%

Where it comes from

The displayed formula is the working relation. TCP = 1 / (1 + exp(−4 γ₅₀ (D − TCD₅₀)/TCD₅₀)). Population dose–response. Usual reference: Brahme / Okunieff. Derive it in the specialty lesson, then return here to pin the numbers.

Reference: Brahme / Okunieff

Assumptions & limits

Population, not an individual. Homogeneous dose, no time factor, no hypoxia distribution. γ₅₀ already includes inter-patient heterogeneity; do not also smear D.

Pitfalls

α/β is a model parameter, not a measured organ. BED from incomplete repair or a changed overall time is not the simple n·d·(1+d/(α/β)). Never EQD2 a stereotactic dose with an α/β you did not state. Population, not an individual. Homogeneous dose, no time factor, no hypoxia distribution. γ₅₀ already includes inter-patient heterogeneity; do not also smear D.

Keep this

Always write α/β and the fraction size next to a BED or EQD2. Population, not an individual. Homogeneous dose, no time factor, no hypoxia distribution. γ₅₀ already includes inter-patient heterogeneity; do not also smear D.

In this specialty

Radiobiology