Physica

05 Biology

Lea–Catcheside g-factor

Incomplete-repair factor for a continuous irradiation of duration T.

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Simulation

Lea–Catcheside g-factor — Change the numbers; the scene follows.

Where it works

Linear accelerator

Linear accelerator

Isocenter

In the treated volume — tumour and OARs at isocenter, after the dose has been delivered.

Open this machine

Formula

g=2(μT1+eμT)(μT)2,μ=ln2/T1/2g=\frac{2(\mu T-1+e^{-\mu T})}{(\mu T)^2},\quad \mu=\ln2/T_{1/2}

Variables

Results

  • g

    g-factor

    0.0861

  • μ

    Repair constant

    0.4621h⁻¹

  • BED

    Biologically effective dose

    55.831Gy

Curve

Explanation

g=2(μT1+eμT)(μT)2,μ=ln2/T1/2g=\frac{2(\mu T-1+e^{-\mu T})}{(\mu T)^2},\quad \mu=\ln2/T_{1/2}

What it means

The Lea–Catcheside g-factor reduces the quadratic dose term when irradiation is protracted, because some sublethal damage is repaired during the exposure. g → 1 for an acute dose and g → 0 for a very long LDR treatment. BED = D (1 + g D/(α/β)). This is a working relation in Radiobiology.

Where it is used

Clinically it sits on the Linear accelerator — Isocenter. In the treated volume — tumour and OARs at isocenter, after the dose has been delivered. Radiobiology sits between the prescription and the organ-at-risk: LQ, BED, EQD2, and why 2 Gy is not 2 Gy if the fraction size changed. Use it to compare regimens, not to invent one.

Linear accelerator · Open this machine

How to use it

Repair T½ often 0.5–1.5 h for early effects, longer for some late tissues. A 48 h LDR prostate implant has g ≪ 1, which is why 30 Gy LDR is not 30 Gy HDR. Change one input and watch the curve and the simulation follow.

Symbols

  • TIrradiation time48 h
  • Repair half-time1.5 h
  • DDose30 Gy
  • α/βAlpha/beta3 Gy

Worked example

A typical case from the default values: T = 48 h (Irradiation time); T½ = 1.5 h (Repair half-time); D = 30 Gy (Dose); α/β = 3 Gy (Alpha/beta). Substituting into the relation gives g = 0.0861; μ = 0.4621 h⁻¹; BED = 55.831 Gy. These are teaching numbers — align them with your machine.

Typical values give

  • g = 0.0861
  • μ = 0.4621h⁻¹
  • BED = 55.831Gy

Where it comes from

The displayed formula is the working relation. Incomplete-repair factor for a continuous irradiation of duration T. Usual reference: Lea & Catcheside / Dale. Derive it in the specialty lesson, then return here to pin the numbers.

Reference: Lea & Catcheside / Dale

Assumptions & limits

Mono-exponential repair, constant dose rate, one session. Fractionated incomplete repair uses a different θ = e^{−μΔT} formula (not this g).

Pitfalls

α/β is a model parameter, not a measured organ. BED from incomplete repair or a changed overall time is not the simple n·d·(1+d/(α/β)). Never EQD2 a stereotactic dose with an α/β you did not state. Mono-exponential repair, constant dose rate, one session. Fractionated incomplete repair uses a different θ = e^{−μΔT} formula (not this g).

Keep this

BED = D (1 + g D / (α/β)) for a single continuous session (LDR, PDR pulse as approx.).

In this specialty

Radiobiology