Physica

03 Nuclear

Mo-99 / Tc-99m generator

Daughter activity in transient equilibrium after ingrowth time.

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Simulation

Mo-99 / Tc-99m generator — Change the numbers; the scene follows.

Where it works

Hot lab

Hot lab

Generator

At the Mo-99/Tc-99m generator — elution yield, secular equilibrium, Mo breakthrough.

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Formula

A2(t)=fA1(0)λ2λ2λ1(eλ1teλ2t)A_2(t)=f A_1(0)\frac{\lambda_2}{\lambda_2-\lambda_1}\left(e^{-\lambda_1 t}-e^{-\lambda_2 t}\right)

Variables

Results

  • A_Tc

    Technetium activity

    13.5157GBq

  • A_Tc/A_Mo(0)

    Ratio

    0.6758

Curve

Explanation

A2(t)=fA1(0)λ2λ2λ1(eλ1teλ2t)A_2(t)=f A_1(0)\frac{\lambda_2}{\lambda_2-\lambda_1}\left(e^{-\lambda_1 t}-e^{-\lambda_2 t}\right)

What it means

A Mo-99/Tc-99m generator is a classic transient-equilibrium parent–daughter pair. Tc-99m grows in with T½ = 6.02 h while Mo-99 (66 h) slowly decays; activity peaks around 24 h after a perfect elution. Branching to Tc-99m is ~86%. This is a working relation in Nuclear medicine.

Where it is used

Clinically it sits on the Hot lab — Generator. At the Mo-99/Tc-99m generator — elution yield, secular equilibrium, Mo breakthrough. Nuclear-medicine relations sit in the hot lab, on the camera, and in the voxel: decay, SUV, TOF, and counting statistics. They decide whether an uptake is real or a clock error.

Hot lab · Open this machine

How to use it

Enter Mo activity at t = 0 (post-elution). The curve over 72 h shows ingrowth. Real generators never reach the theoretical maximum because of incomplete elution and Tc-99 (ground state) buildup. Change one input and watch the curve and the simulation follow.

Symbols

  • A_MoMolybdenum activity20 GBq
  • T½_MoMo half-life66 h
  • T½_TcTc half-life6.02 h
  • fBranching fraction0.86
  • tIngrowth time24 h

Worked example

A typical case from the default values: A_Mo = 20 GBq (Molybdenum activity); T½_Mo = 66 h (Mo half-life); T½_Tc = 6.02 h (Tc half-life); f = 0.86 (Branching fraction); t = 24 h (Ingrowth time). Substituting into the relation gives A_Tc = 13.5157 GBq; A_Tc/A_Mo(0) = 0.6758. These are teaching numbers — align them with your machine.

Typical values give

  • A_Tc = 13.5157GBq
  • A_Tc/A_Mo(0) = 0.6758

Where it comes from

The displayed formula is the working relation. Daughter activity in transient equilibrium after ingrowth time. Usual reference: Cherry, generators. Derive it in the specialty lesson, then return here to pin the numbers.

Reference: Cherry, generators

Assumptions & limits

Bateman equation with two species and a constant branching fraction. No Mo breakthrough, no Tc-99m remaining after elution (assumes perfect milk-out at t=0).

Pitfalls

Activity is not counts. SUV needs the true injected activity, the residual, and the correct decay time — a clock off by 10 min on ¹⁸F is a several-percent error. Do not compare SUVs across reconstructions. Bateman equation with two species and a constant branching fraction. No Mo breakthrough, no Tc-99m remaining after elution (assumes perfect milk-out at t=0).

Keep this

f ≈ 0.86 branching to Tc-99m. T½(Mo)=66 h, T½(Tc)=6.02 h.

In this specialty

Nuclear medicine