Physica

04 Protection

Photoneutron TVL (concrete)

n_TVL = log₁₀(Ḣ / P). Concrete TVL for giant-resonance neutrons ~ 20–30 cm.

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Simulation

Photoneutron TVL (concrete) — Change the numbers; the scene follows.

Where it works

Treatment vault

Treatment vault

Primary barrier

In the bunker maze and barriers — time, distance, TVL, WUT, and weekly controlled-area dose.

Open this machine

Formula

x=nTVL,n=log10(H˙unshielded/P)x=n\,\mathrm{TVL},\quad n=\log_{10}(\dot H_{\mathrm{unshielded}}/P)

Variables

Results

  • n_TVL

    Number of TVLs

    2

  • x

    Concrete thickness

    50cm

Explanation

x=nTVL,n=log10(H˙unshielded/P)x=n\,\mathrm{TVL},\quad n=\log_{10}(\dot H_{\mathrm{unshielded}}/P)

What it means

Above ~8–10 MV the linac grows photoneutrons in the target and jaws (giant dipole resonance). Neutrons do not care about lead — they care about hydrogen (concrete, polyethylene, borated mix). A primary photon wall that is already 2 m of concrete is usually enough for neutrons too; a lead door is not, and needs a hydrogenous core. This calculator turns an unshielded neutron Ḣ into a concrete thickness. This is a working relation in Radiation protection.

Where it is used

Clinically it sits on the Treatment vault — Primary barrier. In the bunker maze and barriers — time, distance, TVL, WUT, and weekly controlled-area dose. Protection equations are the wall, the occupancy factor, and the badge: time, distance, shielding, and WUT. They turn a room into a legal design.

Treatment vault · Open this machine

How to use it

Enter unshielded neutron dose rate at the point (mSv/h), the allowed rate P (mSv/h), and TVL (default 25 cm concrete). Read n and thickness. Typical maze-door neutron Ḣ is tens of μSv/h at 18 MV. Change one input and watch the curve and the simulation follow.

Symbols

  • Unshielded rate0.05 mSv/h
  • PAllowed rate0.0005 mSv/h
  • TVLTenth-value layer25 cm

Worked example

A typical case from the default values: Ḣ = 0.05 mSv/h (Unshielded rate); P = 0.0005 mSv/h (Allowed rate); TVL = 25 cm (Tenth-value layer). Substituting into the relation gives n_TVL = 2; x = 50 cm. These are teaching numbers — align them with your machine.

Typical values give

  • n_TVL = 2
  • x = 50cm

Where it comes from

The displayed formula is the working relation. n_TVL = log₁₀(Ḣ / P). Concrete TVL for giant-resonance neutrons ~ 20–30 cm. Usual reference: NCRP 151 / IAEA SRS 47. Derive it in the specialty lesson, then return here to pin the numbers.

Reference: NCRP 151 / IAEA SRS 47

Assumptions & limits

Single TVL, no first/equilibrium split, no capture-γ in concrete (which may need a few cm of extra lead on the occupied side). Maze scatter of neutrons is a McGinley-type calculation, not a slab TVL.

Pitfalls

Tenth-value layers are for the broad beam in that material and that energy — not a photocopy from another bunker. Occupancy T is not a guess; it is a use pattern. Inverse-square fails against a large scatter source. Single TVL, no first/equilibrium split, no capture-γ in concrete (which may need a few cm of extra lead on the occupied side). Maze scatter of neutrons is a McGinley-type calculation, not a slab TVL.

Keep this

Time, distance, shielding — in that order — then calculate the wall. Single TVL, no first/equilibrium split, no capture-γ in concrete (which may need a few cm of extra lead on the occupied side). Maze scatter of neutrons is a McGinley-type calculation, not a slab TVL.

In this specialty

Radiation protection