Now playing · 01 Therapy
Homogeneity index ICRU 83
HI = 0.07000
H
I
=
D
2
%
−
D
98
%
D
50
%
\mathrm{HI}=\frac{D_{2\%}-D_{98\%}}{D_{50\%}}
HI
=
D
50%
D
2%
−
D
98%
HI = (D2% − D98%) / D50%. Zero is perfectly homogeneous.
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