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Photon dmax versus energy

dmax_rule = 1.500 cm

dmax⁡≈0.25 EMV cm(6 MV:1.5 cm; 18 MV:3.3 cm)d_{\max}\approx 0.25\,E_{\mathrm{MV}}\ \mathrm{cm}\quad (6\,\mathrm{MV}:1.5\,\mathrm{cm};\ 18\,\mathrm{MV}:3.3\,\mathrm{cm})

Teaching rule: dmax (cm) ≈ 0.25 E(MV) for flattening-filter beams, clamped 0.5–5 cm.

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