Now playing · 04 Protection
Required thickness
x = 16.61 mm
x
=
H
V
L
⋅
log
2
(
1
/
B
)
=
T
V
L
⋅
log
10
(
1
/
B
)
x = \mathrm{HVL}\cdot\log_2(1/B) = \mathrm{TVL}\cdot\log_{10}(1/B)
x
=
HVL
⋅
lo
g
2
(
1/
B
)
=
TVL
⋅
lo
g
10
(
1/
B
)
Barrier thickness that yields transmission B.
Laser