Now playing · 07 MRI
Ernst angle
θ_E = 9.336 °
θ
E
=
arccos
(
e
−
T
R
/
T
1
)
\theta_E = \arccos\left(e^{-\mathrm{TR}/T_1}\right)
θ
E
=
arccos
(
e
−
TR
/
T
1
)
Flip angle that maximises signal for given TR and T1.
Laser