Now playing · 00 Foundations
Linear and mass attenuation
μ = 1.695 cm⁻¹
μ
=
(
μ
/
ρ
)
ρ
,
H
V
L
=
ln
2
/
μ
,
T
V
L
=
ln
10
/
μ
\mu=(\mu/\rho)\rho,\quad \mathrm{HVL}=\ln2/\mu,\quad \mathrm{TVL}=\ln10/\mu
μ
=
(
μ
/
ρ
)
ρ
,
HVL
=
ln
2/
μ
,
TVL
=
ln
10/
μ
μ = (μ/ρ) ρ. HVL = ln 2 / μ, TVL = ln 10 / μ.
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