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Exposure and air kerma

X = 0.0002580 C/kg

X=Qmair,Kair=X(We),1 R=8.76 mGyX=\frac{Q}{m_{\mathrm{air}}},\quad K_{\mathrm{air}}=X\left(\frac{W}{e}\right),\quad 1\,\mathrm{R}=8.76\,\mathrm{mGy}

X = Q/m_air. 1 R = 2.58×10⁻⁴ C/kg → K_air = 0.00876 Gy/R (W/e = 33.97 J/C).

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