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AEC mAs versus thickness

mAs₂ = 43.20

mAs2mAs1=eμΔx,double every 4–5 cm\frac{\mathrm{mAs}_2}{\mathrm{mAs}_1}=e^{\mu\Delta x},\quad \text{double every }4\text{–}5\,\mathrm{cm}

mAs₂ / mAs₁ = exp(μ Δx) at fixed kVp, or the 4–5 cm doubling rule.

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