Now playing · 06 Dose
Temperature-pressure correction
k_TP = 1.000
k
T
P
=
273.2
+
T
295.2
⋅
101.33
P
k_{TP}=\frac{273.2+T}{295.2}\cdot\frac{101.33}{P}
k
T
P
=
295.2
273.2
+
T
⋅
P
101.33
Open-air chamber correction to 22 °C and 101.33 kPa.
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